9. Converting (0111011.100)2 to base 16 yields which of the following results?

  1. 73.8
  2. 3C.4
  3. 3B.8
  4. 73.4
  5. 3B.4

3 is CORRECT. Adding a front and back end zero to the number (0111011.100)2 results in (0011011.0100)2. Grouping the bits in groups of 4 about the radix point, interpret the number as follows: 0011 = 3; 1011 = A; Dot 1000 = 8. Therefore, (0111011.100)2 = (3B.8), using the 2^k conversion method.

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