1. ABCDEF
2. AB
3. AB + CD + EF
4. A + B + C + D + E + F
5. A + B(C+D(E+F))

2 is CORRECT. Repeated application of the absorption theorem x + xy = x in the expression gives the desired result:

AB + ABC      + ABCD      +  ABCDE     + ABCDEF
--------
AB + ABC = AB                                        (x = AB, y = C)
           ---------
           AB + ABCD = AB                            (x = AB, y = CD)
                       ---------
                       AB + ABCDE = AB               (x = AB, y = CDE)
                                    -----------
                                    AB + ABCDEF = AB (x = AB, y = CDEF)

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