9. A ROM having 9 address lines and 16 outputs is given. What is the total capacity = C? Note: K = 1024 = 2^10

3 is CORRECT. The formula for ROM capacity is C = 2^n x m. Where n = number of inputs, m = number of outputs. Therefore we have

     C = 2^9 x 16, or,  

       = 2^9 x 2^4 or,

       = 2^13 bits.

Now Let's express this in terms of K = 2^10...

	2^13 = 2^3 x 2^10

     	= 8 x K

     	= 8*K